JOURNAL OF GEOPHYSICAL RESEARCH, VOL. 108, NO. B2, 2119, doi:10.1029/2002JB001884, 2003
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[15] We assume that a sliding (mode II) crack of length 2a develops in snow near the underlying rigid base and propagates symmetrically at both tips (Figure 1). Consider first that the residual shear stress,
r, that develops in this sliding crack after large slip is negligible,
r
0. By arguments of symmetry, the longitudinal normal stress,
, in the sliding layer must vanish at the point of symmetry, i.e.,
0 at x = 0, where x is the longitudinal coordinate measured from the center of the crack. The equilibrium condition of an element dx of the layer requires that (
+ d
)D -
D -
gDsin
= 0 or d
/dx =
gsin
(for
= 0, Figure 1), which means that
where D is snow thickness and
is the mass density of snow (both assumed to be uniform and equal to the means calculated from thickness and density data) and g is magnitude of gravity acceleration. Beyond the crack (x > a),
= 0, and the weight of the snow slab is transmitted to the base entirely by shear stresses. Longitudinally, the upper half of the sliding layer is in tension and the lower half in compression. Evidently, a tensile break must eventually occur in the upper half, but it seems reasonable to assume that this usually happens only after stability loss and is not what triggers the avalanche [McClung, 1981].
[16] The complementary strain energy of one half of the sliding layer is
Here E
is the effective Young's modulus of the sliding snow layer, b is the lateral width of this layer, and
N is the nominal shear stress, defined as the shear stress that would be needed to support the weight of the sliding layer if there were no crack, i.e.,
The nominal stress,
N, is a load parameter and represents the component, in the direction of slope, of the gravity force per unit base area. The energy release rate,
, is
In LEFM, the fracture criterion is
= GII, where GII is the mode II fracture energy of snow, i.e., the energy required to form a sliding crack of a unit area, considered as a material constant. Setting
= GII, one gets nominal stress at failure
Here
is the relative crack length, which will be discussed later. From now on,
N will denote nominal shear strength.
[17] From experience with other size effect problems [Ba
ant and Planas, 1998], one may expect
to be constant when geometrically similar structures of different sizes D are compared. Under that assumption, the LEFM size effect according to (5) is
N
D-1/2, which must have been expected for more fundamental reasons [Ba
ant, 1984, 1993]. The approximate size independence of
will be better justified later.

Citation: Size effect law and fracture mechanics of the triggering of dry snow slab avalanches, J. Geophys. Res., 108(B2), 2119, doi:10.1029/2002JB001884, 2003.